document.write( "Question 1119803: An astronaut on the moon throws a baseball upward. The astronaut is 6ft, 6 in tall, and the initial velocity of the ball is 40 ft per second. The height s of the ball in feet is given by the equation s=-2.7t squared+40t+6.5, where t is the number of seconds after the ball was thrown. After how many seconds is the ball 22ft above the moons surface? \n" ); document.write( "

Algebra.Com's Answer #735421 by josmiceli(19441) $\"\"$ $\"About$

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$\"+s=+-2.7t+%5E2+%2B+40t+%2B+6.5+\"$
\n" ); document.write( " $\"+22+=+-2.7t%5E2+%2B+40t+%2B+6.5+\"$
\n" ); document.write( " $\"+2.7t%5E2+-+40t+%2B+15.5+=+0+\"$
\n" ); document.write( " $\"+27t%5E2+-+400t+%2B+155+=+0+\"$
\n" ); document.write( "Solve for $\"+t+\"$ using quadratic formula
\n" ); document.write( "You will get 2 results. One is for when
\n" ); document.write( "The ball is on the way up and the other
\n" ); document.write( "Is for when the ball is going down \n" ); document.write( "

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