document.write( "Question 1119792: If I'm using an 8-litre container in which I wish to mix Sodium Hypochlorite(SH) at 12% with water to give me a 1% mix. How much sodium Hypochlorite(SH) would I need to add?
\n" ); document.write( "My thinking is 80ml because 8 litres is 8000ml and 1% of 8000 is 80. Do I also need to take into consideration the strength of the Sodium Hypochlorite as in if the (SH) was a 10% strength that would give 1% but with it being 12% would that be a 1.2% mix? so is this a variable I have to take into consideration and if so how would I adjust depending on increased strengths of (SH)
\n" ); document.write( "Thank you, hope it's not too long-winded.
\n" ); document.write( "Regards
\n" ); document.write( "Mark \n" ); document.write( "
Algebra.Com's Answer #735416 by greenestamps(13200)\"\" \"About 
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\n" ); document.write( "Your method of solution is fine; and you definitely need to consider the percentage of the original solution in finding the answer.

\n" ); document.write( "The final mixture is to be 1% SH; 1% of 8000ml is 80ml. So you need 80ml of SH in the final mixture.

\n" ); document.write( "If x is the number of ml of the 12% solution you use, then the amount of SH is .12x. So you need to have

\n" ); document.write( "\".12x+=+80\"
\n" ); document.write( "\"x+=+80%2F.12+=+2000%2F3\" or 666 2/3 ml

\n" ); document.write( "You want to use 666 2/3 ml of the original solution and 8000 - 666 2/3 = 7333 1/3 ml of water to get the desired mixture.

\n" ); document.write( "And here is a common sense solution method you can use in a problem like this, whren you are diluting a given solution with pure water.

\n" ); document.write( "The concentration of the final mixture is 1/12 that of the solution you started with. That means 1/12 of the mixture must be what you started with, and 11/12 must be the water you added.

\n" ); document.write( "1/12 of 8000ml = 666 2/3 ml of the original solution;
\n" ); document.write( "11/12 of 8000ml = 7333 1/3 ml of water \n" ); document.write( "
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