document.write( "Question 1119777: You are performing a two-tailed test with test statistic z=−2.958, find the p-value accurate to 4 decimal places.\r
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Algebra.Com's Answer #735396 by Theo(13342)![]() ![]() You can put this solution on YOUR website! the p-value for a z-score of -2.958 is equal to .0015 rounded to 4 decimal places.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "this was determined using the TI-84 Plus scientific calculator.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the calculator told me that the p-value was .0015482793.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "this yielded .0015 when rounded to 4 decimal places.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "if you looked it up in the normal distribution z-score full table, you would find that:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "z-score of -2.95 yielded a p-value of .0016. \n" ); document.write( "z-score of -2.96 yielded a p-value of .0015.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "since the z-score of -2.958 is closer to -2.96, you would use .0015 as the p-value.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "here's the normal distribution z-score full table that i used.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "http://www.z-table.com/\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |