document.write( "Question 1119759: On a table in a doctor’s office are five Motor Trend magazines, six Parenting magazines, and three Sports Illustrated magazines. If a patient randomly selects three magazines, determine the probability that
\n" );
document.write( "a. three Motor Trend magazines are selected.
\n" );
document.write( "b. two Parenting magazines and one Sports Illustrated magazine are selected.
\n" );
document.write( "c. no Parenting magazine is selected.
\n" );
document.write( "d. at least one Parenting magazine is selected
\n" );
document.write( " \n" );
document.write( "
Algebra.Com's Answer #735360 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! 14 magazines \n" ); document.write( "(5/14)(4/13)(3/12)=0.0275 ANSWER a \n" ); document.write( "three ways this can happen, PPS PSP SPP \n" ); document.write( "probability of one of these is (6/14)(5/13)(3/12)--the others will have the same denominator and the same numerator, but the order in the numerator is different, which doesn't matter \n" ); document.write( "That probability is 0.0412, so the overall probability is three times that or 0.1236 ANSWER b \n" ); document.write( "No parenting means only of the others are chosen or (8/14)*(7/13)(6/12)=0.1538 ANSWER c \n" ); document.write( "At least one parenting would be the complement or 0.8462 ANSWER d \n" ); document.write( " |