document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1119678>Question 1119678</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Calculate the total area of the region described. Do not count area beneath the x-axis as negative.<BR>\n" );
document.write( "Bounded by the curve y=(sqrt.x), the x-axis, and the lines x = 0 and x = 1 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #735282 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=735282\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Calculate the total area of the region described. <BR>\n" );
document.write( "Bounded by the curve y=sqrt(x), the x-axis, and the lines x = 0 and x = 1<BR>\n" );
document.write( "----<BR>\n" );
document.write( "y = x^(1/2)<BR>\n" );
document.write( "INT = F(x) = x^(3/2)/(3/2) = 2x^(3/2)/3 --- ignore the constant of integration.<BR>\n" );
document.write( "F(1) = 2/3<BR>\n" );
document.write( "F(0) = 0<BR>\n" );
document.write( "Area = 2/3 sq units<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );