document.write( "Question 1119680: J is 3 years older than K. If you square K's age and add twice J's age, the result is 69. What are their ages? \n" ); document.write( "

Algebra.Com's Answer #735279 by Tatiana_Stebko(1539) $\"\"$ $\"About$

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Let K be $\"x\"$ years old, then J be $\"%28x%2B3%29\"$ years old,.
\n" ); document.write( "If you square K's age $\"%28x%5E2%29\"$ and add twice J's age $\"2%2A%28x%2B3%29\"$ , the result is $\"x%5E2%2B2%2A%28x%2B3%29\"$ equal to $\"69\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"x%5E2%2B2%2A%28x%2B3%29=69\"$
\n" ); document.write( " $\"x%5E2%2B2x%2B6-69=0\"$
\n" ); document.write( " $\"x%5E2%2B2x-63=0\"$
\n" ); document.write( " $\"%28x-7%29%28x%2B9%29=0\"$
\n" ); document.write( " $\"x-7=0\"$ or $\"x%2B9=0\"$
\n" ); document.write( " $\"x=7\"$ or $\"x=-9\"$ - it's an extraneous root (since it's negative)
\n" ); document.write( "K is $\"7+\"$ years old and J is $\"7%2B3=10\"$ years old \n" ); document.write( "

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