document.write( "Question 1119660: a) Find x:
\n" ); document.write( "x^5+ x^4+ x^3+ x^2+1=0
\n" ); document.write( "I have factored it : (x^2+ x+1)(x+1)(x^2-x+1)
\n" ); document.write( "b)Factoring:
\n" ); document.write( "2x^2y^2+2y^2z^2+2x^2z^2-x^4-y^4-z^4 \n" ); document.write( "
Algebra.Com's Answer #735271 by greenestamps(13203)\"\" \"About 
You can put this solution on YOUR website!


\n" ); document.write( "You didn't write the first equation correctly; you left out the linear term.

\n" ); document.write( "\"x%5E5%2Bx%5E4%2Bx%5E3%2Bx%5E2%2Bx%2B1+=+0\"
\n" ); document.write( "\"%28x%2B1%29%28x%5E4%2Bx%5E2%2B1%29+=+0\"
\n" ); document.write( "\"%28x%2B1%29%28%28x%5E4%2B2x%5E2%2B1%29-x%5E2%29+=+0\"
\n" ); document.write( "\"%28x%2B1%29%28%28%28x%5E2%2B1%29%2Bx%29%28%28x%5E2%2B1%29-x%29%29+=+0\"
\n" ); document.write( "\"%28x%2B1%29%28x%5E2%2Bx%2B1%29%28x%5E2-x%2B1%29+=+0\"

\n" ); document.write( "The linear factor gives the only real solution, x = -1. Each of the quadratic factors gives a pair of complex solutions.

\n" ); document.write( "To factor the second expression, we can use a method similar to that used above to factor x^4+x^2+1.

\n" ); document.write( "\"2x%5E2y%5E2%2B2y%5E2z%5E2%2B2x%5E2z%5E2-x%5E4-y%5E4-z%5E4\"
\n" ); document.write( "= \"%28-1%29%28x%5E4%2By%5E4%2Bz%5E4-2x%5E2y%5E2-2x%5E2z%5E2-2y%5E2z%5E2%29\"
\n" ); document.write( "= \"%28-1%29%28%28x%5E4%2By%5E4%2Bz%5E4%2B2x%5E2y%5E2-2x%5E2z%5E2-2y%5E2z%5E2%29-4x%5E2y%5E2%29\"
\n" ); document.write( "= \"%28-1%29%28%28x%5E2%2By%5E2-z%5E2%29%5E2-%282xy%29%5E2%29\"
\n" ); document.write( "= \"%28-1%29%28x%5E2%2By%5E2-z%5E2%2B2xy%29%28x%5E2%2By%5E2-z%5E2-2xy%29\" \n" ); document.write( "
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