document.write( "Question 1119660: a) Find x:
\n" ); document.write( "x^5+ x^4+ x^3+ x^2+1=0
\n" ); document.write( "I have factored it : (x^2+ x+1)(x+1)(x^2-x+1)
\n" ); document.write( "b)Factoring:
\n" ); document.write( "2x^2y^2+2y^2z^2+2x^2z^2-x^4-y^4-z^4
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Algebra.Com's Answer #735267 by Alan3354(69443)\"\" \"About 
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a) Find x:
\n" ); document.write( "x^5+ x^4+ x^3+ x^2+1=0
\n" ); document.write( "I have factored it : (x^2+ x+1)(x+1)(x^2-x+1)
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\n" ); document.write( "Then (x^2+ x+1)(x+1)(x^2-x+1) = 0
\n" ); document.write( "--> x = -1 is the most obvious solution
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\n" ); document.write( "But
\n" ); document.write( "f(x) = x^5+ x^4+ x^3+ x^2+1
\n" ); document.write( "f(-1) = -1 + 1 - 1 + 1 + 1 = 1, not zero, so (x+1) is not a factor.
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\n" ); document.write( "b)Factoring:
\n" ); document.write( "2x^2y^2+2y^2z^2+2x^2z^2-x^4-y^4-z^4
\n" ); document.write( "
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