document.write( "Question 1119622: Solve the system by the method of elimination. (If there is no solution, enter NO SOLUTION. If the system is dependent, enter a for x and enter y in terms of a.)\r
\n" ); document.write( "\n" ); document.write( "1/2x+y=1/8
\n" ); document.write( "5/2x+5y=5/8\r
\n" ); document.write( "\n" ); document.write( "(x,y)
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Algebra.Com's Answer #735228 by greenestamps(13198)\"\" \"About 
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\n" ); document.write( "Multiply the first equation by 5; the result is equal to the second equation.

\n" ); document.write( "Then solving the pair of equations by elimination (subtracting one equation from the other) results in the equation 0 = 0.

\n" ); document.write( "That equation is always true; the two equations are equivalent; they are different forms of the equation for the same straight line; the system of equations is dependent.

\n" ); document.write( "Of course, once you see that the first equation multiplied by 5 is the same as the second equation, you know that is the answer; there is no need to use elimination.

\n" ); document.write( "Then, according to the instructions, let x = a and solve for y in terms of a:

\n" ); document.write( "(1/2)a+y = 1/8
\n" ); document.write( "y = 1/8 - (1/2)a OR y = (1-4a)/8

\n" ); document.write( "The solutions are any ordered pair of the form (a, (1-4a)/8).
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