document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1119621>Question 1119621</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve the system by the method of elimination. (If there is no solution, enter NO SOLUTION. If the system is dependent, enter a for x and enter y in terms of a.)\r<BR>\n" );
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document.write( "3x-6y=8<BR>\n" );
document.write( "-6x+12y=-16\r<BR>\n" );
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document.write( "(x,y) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #735227 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13203)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=735227\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "Multiply the first equation by 2 and add to the second equation.  The result is<br><BR>\n" );
document.write( "0 = 0<br><BR>\n" );
document.write( "That equation is always true.  Any (x,y) value satisfying one equation will satisfy the other.  The equations are equivalent; the two equations are dependent.<br><BR>\n" );
document.write( "So according to the instructions we set x = a and solve for y in terms of a:<br><BR>\n" );
document.write( "3x-6y = 8<BR>\n" );
document.write( "3a-6y = 8<BR>\n" );
document.write( "3a-8 = 6y<BR>\n" );
document.write( "y = (3a-8)/6<br><BR>\n" );
document.write( "The solutions are any ordered pairs in the form (a,(3a-8)/6). </SPAN>\n" );
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