document.write( "Question 1119602: There are 6 people who will sit in a row but out of them James will always be left of Esther and John will always be right of Esther. In how many ways such arrangement can be done?\r
\n" ); document.write( "\n" ); document.write( "Note: i tried solving and got 24 as the answer but there was no 24 in the options. here are the options: \r
\n" ); document.write( "\n" ); document.write( "120
\n" ); document.write( "72
\n" ); document.write( "64
\n" ); document.write( "218.\r
\n" ); document.write( "\n" ); document.write( "Many thanks.
\n" ); document.write( "

Algebra.Com's Answer #735203 by greenestamps(13200)\"\" \"About 
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\n" ); document.write( "Here is another way to solve the problem.

\n" ); document.write( "(1) Place James, Esther, and John in the proper order.
\n" ); document.write( "(2) Have the 4th person choose a place in the line. With 3 people currently in the line, there are 4 choices for where he can stand (left of James, between James and Esther, between Esther and John, or right of John).
\n" ); document.write( "(3) Now there are 4 people in line; the 5th person has 5 choices of where to stand in the line.
\n" ); document.write( "(4) Now there are 5 people in the line; the last person has 6 choices of where to stand in the line.

\n" ); document.write( "The total number of different arrangements with the given restrictions is the product of the numbers of choices the last three people had for where to stand in the line: 4*5*6 = 120.
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