document.write( "Question 1119555: Use the following information below to answer the next two questions.
\n" ); document.write( "In a particular town, 30% of all adults have brown hair. \r
\n" ); document.write( "\n" ); document.write( "18. If three adults are randomly and independently selected for a survey, calculate the probability that all three have brown hair.
\n" ); document.write( "(a) 0.300
\n" ); document.write( "(b) 0.027
\n" ); document.write( "(c) 0.090
\n" ); document.write( "(d) 0.900 \r
\n" ); document.write( "\n" ); document.write( "19. If two adults are randomly and independently selected for a survey, calculate the probability that at least one has brown hair.
\n" ); document.write( "(a) 0.49
\n" ); document.write( "(b) 0.51
\n" ); document.write( "(c) 0.70
\n" ); document.write( "(d) 0.39
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Algebra.Com's Answer #735178 by Theo(13342)\"\" \"About 
You can put this solution on YOUR website!
this looks like a binomial distribution type of problem.\r
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\n" ); document.write( "\n" ); document.write( "p = .3 equals probability that a person has brown hair.
\n" ); document.write( "q = 1 - p = .7 equsls probability that a person doesn't have brown hair.\r
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\n" ); document.write( "\n" ); document.write( "the formula is p(x) = c(n,x) * p^2 * q^(n-x)\r
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\n" ); document.write( "\n" ); document.write( "in the first problem, n = 3 and you are looking for the probability that all 3 have brown hair.\r
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\n" ); document.write( "\n" ); document.write( "formula becomes p(3) = .3^3 * .7^0 * c(3,3).\r
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\n" ); document.write( "\n" ); document.write( "this is equal to .027 * 1 * 1 = .027\r
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\n" ); document.write( "\n" ); document.write( "that would be selection b.\r
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\n" ); document.write( "\n" ); document.write( "in the second problem, n = 2 and you are looking for the probability that at least 1 has brown hair.\r
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\n" ); document.write( "\n" ); document.write( "that would be equal to 1 minus the probability that all 2 do not have brown hair.\r
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\n" ); document.write( "\n" ); document.write( "formula becomes p(0) = .3^0 * .7^2 * c(2,0).\r
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\n" ); document.write( "\n" ); document.write( "this is equal to 1 * .49* 1 = .49\r
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\n" ); document.write( "\n" ); document.write( "that's the probability that none have brown hair.\r
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\n" ); document.write( "\n" ); document.write( "the probability that at least 1 has brown hair would be 1 minus .49 = .51\r
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\n" ); document.write( "\n" ); document.write( "that would be selection b.\r
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\n" ); document.write( "\n" ); document.write( "the complete probabilities should always add up to 1.\r
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\n" ); document.write( "\n" ); document.write( "those complete probabilities are shown in the following excel printout.\r
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