document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=100993>Question 100993</A>: <I><SPAN STYLE=\"word-break: break-all;\">  I need some help on how to solve a mixture solving problem.\r<BR>\n" );
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document.write( "How many gallons of 65% antifreeze and how many gallons of 20% antifreeze should be mixed to obtain 50 gallons of a 56% mixture of antifreeze?\r<BR>\n" );
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document.write( "Thank you! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #73515 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=73515\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x(65%)+(50-x)(20%)=50(56%) ... .65x+10-.2x=28 ... .45x=18 ... x=40\r<BR>\n" );
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document.write( "40 gal of 65% ... 10 gal of 20% </SPAN>\n" );
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