document.write( "Question 1119540: Find the smallest possible value:\r
\n" );
document.write( "\n" );
document.write( " +
+
+
\r
\n" );
document.write( "
\n" );
document.write( "
\n" );
document.write( "\n" );
document.write( "If you can, answer in root and numeral form, please. \n" );
document.write( "
Algebra.Com's Answer #735141 by ikleyn(52776)![]() ![]() You can put this solution on YOUR website! .\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The key to the solution of the problem is to recognize that the given expression is the sum of distances from the point (x,y) \n" ); document.write( "in a coordinate plane to the points (0,0), (0,1), (1,0) and (3,4).\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Theorem\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " For a convex quadrilateral in a plane, the point in the plane which minimizes the sum of the distances from the point to vertices \n" ); document.write( " of the quadrilateral is the intersection of its diagonals.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \r\n" ); document.write( " Similar statement for a triangle leads to Fermat's point of a triangle and is considered as a difficult geometry\r\n" ); document.write( " conception and statement, which goes far beyond and above the elementary geometry level.\r\n" ); document.write( "\r\n" ); document.write( " See this Wikipedia article https://en.wikipedia.org/wiki/Fermat_point .\r\n" ); document.write( "\r\n" ); document.write( " But for a quadrilateral it is ELEMENTARY statement accesible and approachable for starters.\r\n" ); document.write( "\r \n" ); document.write( "\n" ); document.write( "Proof\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \r\n" ); document.write( "Let ABCD be the given quadrilatersl in a plane with the verices A, B, C and D (in this order).\r\n" ); document.write( "\r\n" ); document.write( "Let \"O\" be the intersection point of its diagonals AC and BD.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "And let X be any other point in the plane. \r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "The sum of distances from X to vertices is \r\n" ); document.write( "\r\n" ); document.write( "d(X) = |AX| + |BX| + |CX| + |DX|.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "The sum of distances from O to vertices is \r\n" ); document.write( "\r\n" ); document.write( "d(O) = |AO| + |BO| + |CO| + |DO|.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "By applying the \"triangle inequality\", you have\r\n" ); document.write( "\r\n" ); document.write( "d(O) = (|AO| + |CO|) + (|BO| + |DO|) = |AC| + |BD| < (|AX| + |CX|) + (|BX| + |DX|) = d(X),\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "and the statement is PROVED.\r\n" ); document.write( "\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Therefore, the solution to your problem is THIS:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \r\n" ); document.write( " The point in the plane which gives the minimum to your expression is the intersection point of the segment\r\n" ); document.write( " connecting the points A=(0,0) and C=(3,4) with the segment connecting the points B=(0,1) and D=(1,0).\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "The straight line connecting the points A and C is\r\n" ); document.write( "\r\n" ); document.write( " y =\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "****************** \n" ); document.write( "* * * SOLVED * * * \n" ); document.write( "******************\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |