document.write( "Question 1119530: Find the vertex, focus, length of latus rectum,and the equation of directrix of y^2 - 4y + 4x = 0 \n" ); document.write( "
Algebra.Com's Answer #735139 by greenestamps(13200)\"\" \"About 
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\n" ); document.write( "The equation has a y^2 term, so the parabola opens right or left. Vertex form for the equation of a parabola that opens right or left is

\n" ); document.write( "\"x-h+=+%281%2F%284p%29%29%28y-k%29%5E2\"

\n" ); document.write( "where the vertex is (h,k) and p is the directed distance from the directrix to the vertex and from the vertex to the focus.

\n" ); document.write( "Note with this form of the equation, the length of the latus rectum (perpendicular to the axis of symmetry and through the focus) is |4p|.

\n" ); document.write( "Put the given equation in that form:

\n" ); document.write( "\"y%5E2+-+4y+%2B+4x+=+0\"
\n" ); document.write( "\"y%5E2-4y%2B4+%2B+4x+-4+=+0\"
\n" ); document.write( "\"4x-4+=+-%28y%5E2-4y%2B4%29\"
\n" ); document.write( "\"4%28x-1%29+=+-1%28y-2%29%5E2\"
\n" ); document.write( "\"x-1+=+%281%2F-4%29%28y-2%29%5E2\"
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\n" ); document.write( "This is in vertex form. The vertex is (1,2); p = -4/4 = -1.

\n" ); document.write( "vertex: (1,2)
\n" ); document.write( "focus: p = 1 left of the vertex; at (0,2)
\n" ); document.write( "directrix: p = 1 right of the vertex; x = 2
\n" ); document.write( "length of latus rectum: |4p| = 4
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