document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1119547>Question 1119547</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A mother 41 years old and her daughter is 9 years old. In how many years will the mother be three times as old as her daughter? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #735104 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=735104\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the mother is 41 when her daughter is 9.\r<BR>\n" );
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document.write( "in how many years will the mother be three times as sold as her daughter.\r<BR>\n" );
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document.write( "let x be the number of years.\r<BR>\n" );
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document.write( "the formula is 41 + x = 3 * (9 + x).\r<BR>\n" );
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document.write( "simplify to get 41 + x = 27 + 3x\r<BR>\n" );
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document.write( "subtract 27 from both sides of the equation and subtract x from both sides of the equation to get 41 - 27 = 3x - x\r<BR>\n" );
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document.write( "simplify to get 14 = 2x\r<BR>\n" );
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document.write( "solve for x to get x = 7.\r<BR>\n" );
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document.write( "if this is correct, then 41 + 7 = 3 * (9 + 7).\r<BR>\n" );
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document.write( "simplify to get 48 = 3 * 16.\r<BR>\n" );
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document.write( "since 3 * 16 = 48, this equation is true and the solution is confirmed to be correct.\r<BR>\n" );
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document.write( "the mother is 48 in 7 years.<BR>\n" );
document.write( "the daughter is 16 in 7 years.<BR>\n" );
document.write( "48 is equal to 3 * 16.\r<BR>\n" );
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document.write( "the solution is 7 years.\r<BR>\n" );
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document.write( " </SPAN>\n" );
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