document.write( "Question 1119549: Sally invested a certain amount of money at 5% and another amount twice as large at 6% interest. The total annual income from the investments was 4,250. Find the amount invested in each rate. \n" ); document.write( "
Algebra.Com's Answer #735102 by Theo(13342)\"\" \"About 
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x equals the amount invested at 5%.
\n" ); document.write( "2x equals the amount invested at 6%.\r
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\n" ); document.write( "\n" ); document.write( "the total annual income from the investments was 4250.\r
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\n" ); document.write( "\n" ); document.write( "your formula is .05 * x + .06 * 2x = 4250.\r
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\n" ); document.write( "\n" ); document.write( "simplify to get .05 * x + .12 * x = 4250.\r
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\n" ); document.write( "\n" ); document.write( "combine like terms to get .17 * x = 4250.\r
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\n" ); document.write( "\n" ); document.write( "solve for x to get x = 4250 / .17 = 25000.\r
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\n" ); document.write( "\n" ); document.write( "she invested 25000 at 5% and 50000 at 6%.\r
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\n" ); document.write( "\n" ); document.write( ".05 * 25000 + .06 * 50000 = 1250 + 3000 = 4250.\r
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\n" ); document.write( "\n" ); document.write( "solution looks good.\r
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\n" ); document.write( "\n" ); document.write( "solution is 25,000 was invested at 5% and 50,000 was invested at 6%.\r
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