document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1119517>Question 1119517</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 3(a – b) = 15<BR>\n" );
document.write( "4a = b + 1<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #735085 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=735085\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the second equation is b=4a-1<BR>\n" );
document.write( "substitute into the first for b after distributing<BR>\n" );
document.write( "3a-3b=15<BR>\n" );
document.write( "3a-3(4a-1)=15<BR>\n" );
document.write( "distribute<BR>\n" );
document.write( "3a-12a+3=15<BR>\n" );
document.write( "-9a=12<BR>\n" );
document.write( "a=-4/3<BR>\n" );
document.write( "4a=-16/3<BR>\n" );
document.write( "b=-19/3<BR>\n" );
document.write( "(-4/3, -19/3) ANSWER<BR>\n" );
document.write( "check in first equation<BR>\n" );
document.write( "3(-4/3-(-19/3))=3(15/3)=15 </SPAN>\n" );
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