document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1119507>Question 1119507</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The numerator of a fraction is 7 less than the denominator.If one and one third is added to it,the fraction obtained is 14/9.Find the original fraction? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #735081 by </B><A HREF=/tutors/aboutme.mpl?userid=htmentor><B>htmentor(1343)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=htmentor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=htmentor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=735081\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (x-7)/x + 4/3 = 14/9<BR>\n" );
document.write( "Multiply through by x and simplify:<BR>\n" );
document.write( "x - 7 + (4/3)x = (14/9)x<BR>\n" );
document.write( "x + (12/9)x - (14/9)x = 7<BR>\n" );
document.write( "(7/9)x = 7<BR>\n" );
document.write( "x = 9<BR>\n" );
document.write( "Thus the original fractions is 2/9 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );