document.write( "Question 1119464: find two numbers whose difference is 3 and whose product is 88
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Algebra.Com's Answer #735017 by math_helper(2461)\"\" \"About 
You can put this solution on YOUR website!
Let x = the larger number\r
\n" ); document.write( "\n" ); document.write( "Then (x)(x-3) = 88
\n" ); document.write( " \"+x%5E2+-+3x+-+88+=+0+\"
\n" ); document.write( " \"+%28x-11%29%28x%2B8%29+=+0+\"\r
\n" ); document.write( "\n" ); document.write( "x=11 and/or x=-8
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\n" ); document.write( "\n" ); document.write( "x=11 —> x-3=8, 11*8 = 88… \"+highlight%28matrix%281%2C4%2C%2211+%22%2C+%22+and+%22%2C+%228%22%2C%22+%22%29%29+\" is a solution
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\n" ); document.write( "\n" ); document.write( "x=-8 —> x-3 = -11, -8*-11=88 … \"highlight%28matrix%281%2C4%2C%22-8+%22%2C+%22+and+%22%2C+%22-11%22%2C%22+%22%29%29+\" is a solution
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\n" ); document.write( "\n" ); document.write( "Tutor @Alan3354 must have misspoken, as a quadratic equation most certainly may have integer solutions.
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\n" ); document.write( "No.\r
\n" ); document.write( "\n" ); document.write( "I said if the 2 solutions are NOT integers, then solving a quadratic is necessary.
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\n" ); document.write( "If they are integers, forming a quadratic and then factoring it just adds unneeded lines IF the solutions are integers.
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\n" ); document.write( "PS I intended to edit my answer, but for some reason I'm editing someone else's ???\r
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\n" ); document.write( "To Alan5534 - Yeah, weird, it allowed you to edit my post. Anyway, I get what you are saying now. However, I do think forming the quadratic and then solving is a straightforward method that works every time (at least when there is a real answer), while the guessing at factors may or may not work, depending on the solution. Thanks. \r
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