document.write( "Question 1119464: find two numbers whose difference is 3 and whose product is 88
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Algebra.Com's Answer #735017 by math_helper(2461)![]() ![]() You can put this solution on YOUR website! Let x = the larger number\r \n" ); document.write( "\n" ); document.write( "Then (x)(x-3) = 88 \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x=11 and/or x=-8 \r \n" ); document.write( "\n" ); document.write( "x=11 —> x-3=8, 11*8 = 88… \r \n" ); document.write( "\n" ); document.write( "x=-8 —> x-3 = -11, -8*-11=88 … \r \n" ); document.write( "\n" ); document.write( "—————————————\r \n" ); document.write( "\n" ); document.write( "Tutor @Alan3354 must have misspoken, as a quadratic equation most certainly may have integer solutions. \n" ); document.write( "=========== \n" ); document.write( "No.\r \n" ); document.write( "\n" ); document.write( "I said if the 2 solutions are NOT integers, then solving a quadratic is necessary. \n" ); document.write( "----- \n" ); document.write( "If they are integers, forming a quadratic and then factoring it just adds unneeded lines IF the solutions are integers. \n" ); document.write( "--- \n" ); document.write( "PS I intended to edit my answer, but for some reason I'm editing someone else's ???\r \n" ); document.write( "\n" ); document.write( "———————————— \n" ); document.write( "To Alan5534 - Yeah, weird, it allowed you to edit my post. Anyway, I get what you are saying now. However, I do think forming the quadratic and then solving is a straightforward method that works every time (at least when there is a real answer), while the guessing at factors may or may not work, depending on the solution. Thanks. \r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |