document.write( "Question 1912: Solve by completing the square.\r
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document.write( "z^2 + z = 2 \n" );
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Algebra.Com's Answer #735 by longjonsilver(2297)![]() ![]() You can put this solution on YOUR website! to write the lefthand side as a \"square\" eg \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "so, we would need to find the number \"a\"...so look at the coefficient of the x-term. You have 1z so 2a is equivalent to 1 therefore a itself must be 1/2. If that is so, then \n" ); document.write( "\n" ); document.write( "so, we would need to have \n" ); document.write( "\n" ); document.write( "but we cannot JUST add a 1/4 to one side...we need to add it to both sides, to keep the equation \"unchanged\", so we actually get the following:\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "which becomes\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "so now, taking square root of both sides, we get\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "so z+1/2 = 3/2 or z+1/2 = -3/2\r \n" ); document.write( "\n" ); document.write( "so z=1, or z=-2\r \n" ); document.write( "\n" ); document.write( "Make sense?\r \n" ); document.write( "\n" ); document.write( "cheers \n" ); document.write( "Jon. \n" ); document.write( " |