document.write( "Question 1119438:  he mean of a normal probability distribution is 540; the standard deviation is 95.(Round the final answers to 2 decimal places.)\r
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document.write( "a. 	\r
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document.write( "About what percentage of the observations lie between 445 and 635?\r
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document.write( "  Percentage of observations 	%  \r
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document.write( "b. 	About what percentage of the observations lie between 350 and 730?\r
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document.write( "  Percentage of observations 	%  \r
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document.write( "c. 	About what percentage of the observations lie between 255 and 825?\r
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document.write( "  Percentage of observations 	%   \n" );
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Algebra.Com's Answer #734999 by stanbon(75887)    ![]() You can put this solution on YOUR website! The mean of a normal probability distribution is 540; the standard deviation is 95.(Round the final answers to 2 decimal places.) \r \n" ); document.write( "\n" ); document.write( "a. \n" ); document.write( "About what percentage of the observations lie between 445 and 635? \n" ); document.write( "z(445) = (445-540)/95 = -1 \n" ); document.write( "z(635) = (635-540)/95 = +1 \n" ); document.write( "--- \n" ); document.write( "P(445<= x <=635) = P(-1<= z <=1) = 0.6827 = 68.25% \n" ); document.write( "------------------- \n" ); document.write( "b. About what percentage of the observations lie between 350 and 730? \n" ); document.write( "Use the same procedure. \n" ); document.write( "Ans:: 95.45% \n" ); document.write( "---------------------- \n" ); document.write( "c. About what percentage of the observations lie between 255 and 825? \n" ); document.write( "Use the same procedure. \n" ); document.write( "Ans:: 99.73% \n" ); document.write( "---- \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "-------------- \n" ); document.write( " \n" ); document.write( "  |