document.write( "Question 1119438: he mean of a normal probability distribution is 540; the standard deviation is 95.(Round the final answers to 2 decimal places.)\r
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\n" ); document.write( "a. \r
\n" ); document.write( "\n" ); document.write( "About what percentage of the observations lie between 445 and 635?\r
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\n" ); document.write( " Percentage of observations % \r
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\n" ); document.write( "b. About what percentage of the observations lie between 350 and 730?\r
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\n" ); document.write( " Percentage of observations % \r
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\n" ); document.write( "c. About what percentage of the observations lie between 255 and 825?\r
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Algebra.Com's Answer #734999 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
The mean of a normal probability distribution is 540; the standard deviation is 95.(Round the final answers to 2 decimal places.) \r
\n" ); document.write( "\n" ); document.write( "a.
\n" ); document.write( "About what percentage of the observations lie between 445 and 635?
\n" ); document.write( "z(445) = (445-540)/95 = -1
\n" ); document.write( "z(635) = (635-540)/95 = +1
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\n" ); document.write( "P(445<= x <=635) = P(-1<= z <=1) = 0.6827 = 68.25%
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\n" ); document.write( "b. About what percentage of the observations lie between 350 and 730?
\n" ); document.write( "Use the same procedure.
\n" ); document.write( "Ans:: 95.45%
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\n" ); document.write( "c. About what percentage of the observations lie between 255 and 825?
\n" ); document.write( "Use the same procedure.
\n" ); document.write( "Ans:: 99.73%
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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