document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=100893>Question 100893</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The problem is: \r<BR>\n" );
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document.write( "[(3y-4)/(49-y^2)] + [(2y+1)/(y-7)]\r<BR>\n" );
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document.write( "I know i need to find the LCD but somehow my answer doesnt match the one in the back of the book. My answer is (2y^2+18y-3)/[(y-7)(y+7)]. Can you please help me! Thank you! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #73498 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=73498\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> your technique looks OK ... did you multiply the first numerator by -1? ... y^2-49=(-1)(49-y^2)\r<BR>\n" );
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document.write( "(2y+1)(y+7)=2y^2+15y+7\r<BR>\n" );
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document.write( "2y^2+15y+7-3y+4=2y^2+12y+11 </SPAN>\n" );
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