document.write( "Question 100974This question is from textbook Intermediate Algebra
\n" ); document.write( ": One number is six less than a first number. A third number is twice the first number. If the sum of the three numbers is 306, find the numbers. \n" ); document.write( "
Algebra.Com's Answer #73495 by doukungfoo(195)\"\" \"About 
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Lets call the first number x
\n" ); document.write( "Now define the other numbers in terms of x
\n" ); document.write( "Given: one number is six less than a first number
\n" ); document.write( "second number = x-6
\n" ); document.write( "Given: a third number is twice the first number
\n" ); document.write( "third number = 2x
\n" ); document.write( "Given: the sum of the three numbers is 306
\n" ); document.write( "Now we can write an equation to solve for x (first number)
\n" ); document.write( "(first#)+(second#)+(third#) = 306
\n" ); document.write( "(x) + (x-6) + (2x) = 306
\n" ); document.write( "x + x - 6 + 2x = 306
\n" ); document.write( "4x - 6 = 306
\n" ); document.write( "4x = 312
\n" ); document.write( "x = 78
\n" ); document.write( "Answer: first number is 78
\n" ); document.write( "now we can find the other numbers
\n" ); document.write( "second number = x - 6
\n" ); document.write( "second number = 78 - 6
\n" ); document.write( "second number = 72
\n" ); document.write( "Answer: second number is 72
\n" ); document.write( "third number = 2x
\n" ); document.write( "third number = 2(78)
\n" ); document.write( "third number = 156
\n" ); document.write( "Answer: third number is 156
\n" ); document.write( "Check answers:
\n" ); document.write( "(first#)+(second#)+(third#) = 306
\n" ); document.write( "78 + 72 + 156 = 306
\n" ); document.write( "306 =306\r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "
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