document.write( "Question 1119394: A bank loaned out ​$20,000
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\n" ); document.write( "per year and the rest at 14 %
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\n" ); document.write( "per year. If the interest received in one year totaled ​$2000
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Algebra.Com's Answer #734930 by Theo(13342)\"\" \"About 
You can put this solution on YOUR website!
x = amount loaned at 6%.
\n" ); document.write( "y = amount loaned at 14%.\r
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\n" ); document.write( "\n" ); document.write( "x + y = 20,000\r
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\n" ); document.write( "\n" ); document.write( ".06 * x + .14 * y = 2000\r
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\n" ); document.write( "\n" ); document.write( "these 2 equations need to be solved simultaneously.\r
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\n" ); document.write( "\n" ); document.write( "multiply both sides of the first equation by .06 and leave the second equation as is to get:\r
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\n" ); document.write( "\n" ); document.write( ".06x + .06y = 1200
\n" ); document.write( ".06x + .14y = 2000\r
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\n" ); document.write( "\n" ); document.write( "subtract the first equation from the second to get:\r
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\n" ); document.write( "\n" ); document.write( ".08y = 800\r
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\n" ); document.write( "\n" ); document.write( "solve for y to get y = 800/.08 = 10,000.\r
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\n" ); document.write( "\n" ); document.write( "that makes x = 10,000.\r
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\n" ); document.write( "\n" ); document.write( "x + y = 20,000 so that part checks out.\r
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\n" ); document.write( "\n" ); document.write( ".06 * 10,000 + .14 * 10,000 = 2,000 so that part checks out as well.\r
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\n" ); document.write( "\n" ); document.write( "your solution is that 10,000 was loaned out at 6%.\r
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