document.write( "Question 1119385: I tried looking at some examples but i'm still confused. Can someone help please? thank you. \r
\n" ); document.write( "\n" ); document.write( "A chemical company makes two brands of antifreeze. The first brand is 20% pure antifreeze and the second brand is 70% pure antifreeze. In order to obtain 180 gallons of a mixture that contains 40% pure antifreeze, how many gallons of each brand of antifreeze must be used?
\n" ); document.write( " \n" ); document.write( "

Algebra.Com's Answer #734918 by MathTherapy(10552) $\"\"$ $\"About$

You can put this solution on YOUR website!

\n" ); document.write( "I tried looking at some examples but i'm still confused. Can someone help please? thank you. \r
\n" ); document.write( "\n" ); document.write( "A chemical company makes two brands of antifreeze. The first brand is 20% pure antifreeze and the second brand is 70% pure antifreeze. In order to obtain 180 gallons of a mixture that contains 40% pure antifreeze, how many gallons of each brand of antifreeze must be used?
\n" ); document.write( "

Let amount of 20% antifreeze be T
\n" );
document.write( "Then amount of 70% antifreeze to mix = 180 - T (amount of 20%, plus amount of 70% MUST equal 180 gallons)
\n" );
document.write( "We then get: .2T + .7(180 - T) = .4(180)
\n" );
document.write( ".2T + 126 - .7T = 72
\n" );
document.write( ".2T - .7T = 72 - 126
\n" );
document.write( "- .5T = - 54
\n" );
document.write( "T, or amount of 20% to mix: 
\n" );
document.write( "Amount of 70% antifreeze to mix:  \n" );
document.write( "

\n" );