document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=100964>Question 100964</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The hypotenuse of a right angle triangle is 3 meters longer than twice the length of one of the legs. The measure of the other leg is 12 meters. Find the measure of the hypotenuse of the triangle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #73487 by </B><A HREF=/tutors/aboutme.mpl?userid=edjones><B>edjones(8007)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=edjones><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=edjones><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=73487\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> a=12<BR>\n" );
document.write( "c=2b+3<BR>\n" );
document.write( "a^2+b^2=c^2<BR>\n" );
document.write( "12^2+b^2=(2b+3)^2<BR>\n" );
document.write( "144+b^2=4b^2+12b+9 expand.<BR>\n" );
document.write( "3b^2+12b-135=0 subtract b+144 from both sides.<BR>\n" );
document.write( "3(b-5)(b+9)=0 Factor.<BR>\n" );
document.write( "b=5, b=-9 <BR>\n" );
document.write( "b=5 is the only possible answer because the leg must be positive.<BR>\n" );
document.write( "c=2b+3=2*5+3= 13 meters Ans.<BR>\n" );
document.write( "Check:<BR>\n" );
document.write( "144+25=169<BR>\n" );
document.write( "Ed </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );