document.write( "Question 1119102: If p = (50y^2)^3/81x^3 then prove that log10^p + 3 log 10^x - 6 log 10^y \r
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document.write( "=6-3log10^2 - 4log10^3 \n" );
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Algebra.Com's Answer #734842 by greenestamps(13203) You can put this solution on YOUR website! \n" ); document.write( "Your question has been sitting here for several days, waiting for someone to respond. Probably the reason you haven't gotten a response is that the statement of the problem is not clear. Some parentheses would help; and some of the notation is ambiguous. \n" ); document.write( "I will guess that, for example, your notation \"log10^p\" means \"log of 10 to the power p\", where the logarithm, by default, is base 10. In that case, log10^p is just p. \n" ); document.write( "Using that interpretation of your notation, any interpretation I can see for your definition of p leads to a nonsensical equation. \n" ); document.write( "So take a look at the question as it was given to you, then re-post your question making it clear what the question is. \n" ); document.write( "--------------------------------------------------- \n" ); document.write( "added in response to the \"solution\" posted by \"tutor\" alan3354.... \n" ); document.write( "He has reached a new low in his performance on this site. \n" ); document.write( "I provide a response to a reader's question showing I have made an effort, unsuccessfully, to decipher a reader's question, and suggesting that the reader resubmit the question stating it more clearly. \n" ); document.write( "His response suggests I made that response only to increase the number of questions I have answered. \n" ); document.write( "So by doing that he has increased the number of questions he has answered -- without even addressing the question that was asked. \n" ); document.write( "The logic of it is laughable... except for the fact that readers who submit questions on the site are looking for help. \n" ); document.write( " |