document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1119263>Question 1119263</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Given: angle 2 is congruent to angle 3, angle 1 and 2 are supplementary <BR>\n" );
document.write( "Prove: angle 1 and angle 3 are supplementary </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #734743 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=734743\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> angle 2 = angle 3.\r<BR>\n" );
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document.write( "if angle 2 is supplementary to angle 1, then angle 2 + angle 1 = 180.\r<BR>\n" );
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document.write( "since angle 2 is equal to angle 3, you can replace angle 2 with angle 3 in the equation of angle 2 + angle 1 = 180 to get:\r<BR>\n" );
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document.write( "angle 3 + angle 1 = 180.\r<BR>\n" );
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document.write( "that makes angle 3 and angle 1 supplementary.\r<BR>\n" );
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document.write( " </SPAN>\n" );
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