document.write( "Question 1119200: log[base2](x+1)-log[base4]x=1\r
\n" ); document.write( "\n" ); document.write( "note: book says to change log[base4]x to base 2.
\n" ); document.write( "ANSWER IS {1}.
\n" ); document.write( "Can not figure how they arrived at the answer x 2 days!!! I know how to change from base 4 to base 2.
\n" ); document.write( "

Algebra.Com's Answer #734670 by greenestamps(13206)\"\" \"About 
You can put this solution on YOUR website!


\n" ); document.write( "log[base2] of a number x is twice log[base4] of the same number x, because 4 is 2 squared:

\n" ); document.write( "log[base 4}x = n --> x = 4^n = (2^2)^n = 2^(2n) --> log[base2]x = 2n

\n" ); document.write( "Your book says to change log[base4]x to an equivalent expression involving log[base2]. Since log[base4] of a number is half of log[base2] of the same number, that would introduce fractions into the calculations.

\n" ); document.write( "I would much rather change the log[base2] expression into an equivalent expression using log[base4].

\n" ); document.write( "\"log%282%2C%28x%2B1%29%29-log%284%2Cx%29+=+1\" given equation
\n" ); document.write( "\"2%2Alog%284%2C%28x%2B1%29%29-log%284%2Cx%29+=+1\" convert log base 2 to log base 4
\n" ); document.write( "\"log%284%2C%28x%2B1%29%5E2%29-log%284%2Cx%29+=+1\" n*log(x) = log(x^n)
\n" ); document.write( "\"log%284%2C%28%28%28x%2B1%29%5E2%29%2Fx%29%29+=+1\" log(a)-log(b) = log(a/b)
\n" ); document.write( "\"%28%28x%2B1%29%5E2%29%2Fx+=+4%5E1+=+4\" definition of logarithms
\n" ); document.write( "\"x%5E2%2B2x%2B1+=+4x\"
\n" ); document.write( "\"x%5E2-2x%2B1+=+0\"
\n" ); document.write( "\"%28x-1%29%5E2+=+0\"
\n" ); document.write( "\"x+=+1\"
\n" ); document.write( "
\n" );