document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1119152>Question 1119152</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hi, I have a problem that I don't understand how to solve, where there are two different interest rates. Can you help me with this? \r<BR>\n" );
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document.write( "\"Madge invested $10,000 for one year, part at 8% annual interest and the rest at 12% annual interest.  Her total interest for the year was $944.  How much did she invest at each rate?\"\r<BR>\n" );
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document.write( "Thank you!\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #734646 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13200)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=734646\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "Tutor @ikleyn showed a solution using the traditional algebraic method.<br><BR>\n" );
document.write( "That is a perfectly good method; however, the answer to a problem like this can be obtained much faster and with less work by a different method.<br><BR>\n" );
document.write( "By comparing the actual interest obtained to the amounts that could have been earned at the two separate interest rates, you can determine the ratio in which the money was split between the two investments.<br><BR>\n" );
document.write( "The interest was $944; the interest if the whole amount had been invested at either of the two separate interest rates are $800 and $1200.<br><BR>\n" );
document.write( "The actual interest of $944 is 144/400 (= 36%) of the distance from $800 to $1200<br><BR>\n" );
document.write( "That means 36% of the $10,000, or $3600, was invested at the higher rate of 12%; the remaining $6400 was invested at 8%. </SPAN>\n" );
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