document.write( "Question 1119157: A basketball team sells tickets that cost​ $10, $20,​ or, for VIP​ seats,​ $30. The team has sold 3357 tickets overall. It has sold 157 more​ $20 tickets than​ $10 tickets. The total sales are ​$64 comma 64,640. How many tickets of each kind have been​ sold?\r
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Algebra.Com's Answer #734635 by ikleyn(52781)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "Let x = #of $10 tickets.\r\n" );
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document.write( "Then the number of $20 tickets is (x+157).\r\n" );
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document.write( "Then the number of $30 tickets is the rest  3357 - x - (x+57) = 3300-2x.\r\n" );
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document.write( "The money equation is\r\n" );
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document.write( "10x + 20*(x+57) + 30*(3300-2x) = 64640.\r\n" );
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document.write( "Simplify and solve for x.\r\n" );
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\n" ); document.write( "\n" ); document.write( "The lesson to learn from this solution:\r
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document.write( "    This problem is for ONE unknown - not for three.\r\n" );
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document.write( "        This problem is for ONE unknown - not for three.\r\n" );
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document.write( "            This problem is for ONE unknown - not for three.\r\n" );
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\n" ); document.write( "To see many other similar solved problems, look into the lesson\r
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