document.write( "Question 1119159: In a survey of 100 students, the numbers taking various courses were found to be English, 59; mathematics, 44; chemistry, 48; English and mathematics, 24; English and chemistry, 26; mathematics and chemistry, 31; and courses in all three areas, 16.\r
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document.write( "(a) How many students were taking mathematics, but neither English nor chemistry?\r
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document.write( "(b) How many were taking mathematics and chemistry, but not English?\r
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document.write( "(c) How many were taking English and chemistry, but not mathematics?
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Algebra.Com's Answer #734633 by ikleyn(52788)![]() ![]() You can put this solution on YOUR website! . \n" ); document.write( "In a survey of 100 students, the numbers taking various courses were found to be \n" ); document.write( "English, 59; mathematics, 44; chemistry, 48; English and mathematics, 24; English and chemistry, 26; mathematics and chemistry, 31; \n" ); document.write( "and courses in all three areas, 16.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \r\n" ); document.write( "(a) How many students were taking mathematics, but neither English nor chemistry?\r\n" ); document.write( "\r\n" ); document.write( " M - EM - MC + EMC = 44 - 24 - 31 + 16 = 5.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "(b) How many were taking mathematics and chemistry, but not English?\r\n" ); document.write( "\r\n" ); document.write( " MC - EMC = 31 - 16 = 15.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "(c) How many were taking English and chemistry, but not mathematics?\r\n" ); document.write( "\r\n" ); document.write( " EC - EMC = 26 - 16 = 10.\r\n" ); document.write( "\r \n" ); document.write( "\n" ); document.write( "Solved.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "-------------\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "In this solution, two-letter abbreviation means intersection of two sub-sets.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |