document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1119140>Question 1119140</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A can is made in the shape of a right circular cylinder and is to<BR>\n" );
document.write( "hold one pint. (For dry goods, one pint is equal to 33.6 cubic inches.\r<BR>\n" );
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document.write( "(a) Find an expression for the volume V of the can in terms of the height h and the base<BR>\n" );
document.write( "radius r.<BR>\n" );
document.write( "(b) Find an expression for the surface area S of the can in terms of the height h and the<BR>\n" );
document.write( "base radius r. (Hint: The top and bottom of the can are circles of radius r and the side<BR>\n" );
document.write( "of the can is really just a rectangle that has been bent into a cylinder.)<BR>\n" );
document.write( "(c) Using the fact that V = 33.6, write S as a function of r and state its applied domain.<BR>\n" );
document.write( "(d) Use your graphing calculator to find the dimensions of the can which has minimal surface<BR>\n" );
document.write( "area. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #734626 by </B><A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><B>josgarithmetic(39625)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=734626\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Volume:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=h%2Api%2Ar%5E2=336 ALIGN=MIDDLE  ALT=\"h%2Api%2Ar%5E2=336\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Surface Area:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2h%2Api%2Ar%2B2pi%2Ar%5E2 ALIGN=MIDDLE  ALT=\"2h%2Api%2Ar%2B2pi%2Ar%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "You should be able to follow instructions in the questions (c) and (d)  to do those. </SPAN>\n" );
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