document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1119139>Question 1119139</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the value of 1/&#8730;3-&#8730;2-1 correct upto three decimal places if&#8730;2= 1.414 ,&#8730;6=2.45 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #734608 by </B><A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><B>josgarithmetic(39617)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=734608\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The expression looks like  1/sqrt(3)-sqrt(2)-1.  That should look like  <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=1%2Fsqrt%283%29-sqrt%282%29-1 ALIGN=MIDDLE  ALT=\"1%2Fsqrt%283%29-sqrt%282%29-1\"   DISABLED_style= \"max-width:90%; height:auto;\" >.\r<BR>\n" );
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document.write( "If that is not what you have to start with, then rewrite your expression properly.\r<BR>\n" );
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document.write( "The approximate value for the expression as written in your post:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=-1.837 ALIGN=MIDDLE  ALT=\"-1.837\"   DISABLED_style= \"max-width:90%; height:auto;\" > </SPAN>\n" );
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