document.write( "Question 1119103: If x^2 + y^2 =23xy, prove that log {(x+y)/5} = (1/2) (log x + log y) \n" ); document.write( "
Algebra.Com's Answer #734564 by greenestamps(13198)\"\" \"About 
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\n" ); document.write( "\"x%5E2%2By%5E2+=+23xy\"
\n" ); document.write( "\"x%5E2%2B2xy%2By%5E2+=+25xy\"
\n" ); document.write( "\"%28x%2By%29%5E2+=+25xy\"
\n" ); document.write( "\"%28%28x%2By%29%5E2%29%2F25+=+xy\"
\n" ); document.write( "\"%28%28x%2By%29%2F5%29%5E2+=+xy\"
\n" ); document.write( "\"log%28%28%28x%2By%29%2F5%29%5E2%29+=+log%28%28xy%29%29\"
\n" ); document.write( "\"2%2Alog%28%28%28x%2By%29%2F5%29%29+=+log%28%28x%29%29%2Blog%28%28y%29%29\"
\n" ); document.write( "\"log%28%28%28x%2By%29%2F5%29%29+=+%281%2F2%29%28log%28%28x%29%29%2Blog%28%28y%29%29%29\"
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