document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1119070>Question 1119070</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A carton of 18 lightbulbs includes 5 that are defective.  If two bulbs are drawn at random, what are the probabilities that\r<BR>\n" );
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document.write( "	(a)  neither bulb will be defective\r<BR>\n" );
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document.write( "	(b)  exactly 1 bulb will be defective\r<BR>\n" );
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document.write( "	(c )  both bulbs will be defective\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #734510 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=734510\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 13 are not defective, so it would be 13/18*12/17, after one non-defective is removed.  Product is 0.5098<BR>\n" );
document.write( "1 defective is <BR>\n" );
document.write( "*first one 5/18*13/17<BR>\n" );
document.write( "*second one 13/18*5/17; those two products are the same, so multiply by 2, the number of ways, and it is 0.4276.<BR>\n" );
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document.write( "both defective is 5/18*4/17=20/304, or 0.0658.  Those three add to 1.0032, which is 1 with rounding error. </SPAN>\n" );
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