document.write( "Question 1119052: The population of a town is 10,000 people. The population is growing according to the function P(t) = 10,000(2^0.03t), where t is the number of years from the present and P is the population. What is the estimated population of the town after 3 years.
\n" ); document.write( " I can set the problem up but have a difficult time inputting in my calculator TI-84 plus
\n" ); document.write( "P(t) =10,000 (2^.03t)
\n" ); document.write( "P (3) = 10^4 (2^,03(3)
\n" ); document.write( "P (3) 10^4 (2^.09) after inputting this should give me the answer.
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Algebra.Com's Answer #734494 by Theo(13342)\"\" \"About 
You can put this solution on YOUR website!
i just so happen to have the TI-84 plus so you're in luck.\r
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\n" ); document.write( "\n" ); document.write( "the function is p(t) = 10,000 * 2 ^ .03t.\r
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\n" ); document.write( "\n" ); document.write( "that's a strange looking formula.\r
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\n" ); document.write( "\n" ); document.write( "are you sure it isn't p(t) = 10,000 * e ^ .03t ?????\r
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\n" ); document.write( "\n" ); document.write( "that would make more sense.\r
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\n" ); document.write( "\n" ); document.write( "the letter e represents the scientific constant of 2.718281828...\r
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\n" ); document.write( "\n" ); document.write( "that formula then gives you the continuous growth rate, which is what is usually used in these type of problems.\r
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\n" ); document.write( "\n" ); document.write( "i'll do both, just in case you really meant 2.\r
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\n" ); document.write( "\n" ); document.write( "first i'll use the 2.\r
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\n" ); document.write( "\n" ); document.write( "10,000 * 2 ^ .03t, when t is equal to 3, is calculated as follows in the TI-84 Plus calculator.\r
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\n" ); document.write( "\n" ); document.write( "you enter 10000*2^(.03*3) and the calculator tells you the answer is 10643.70182 after you hit ENTER.\r
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\n" ); document.write( "\n" ); document.write( "your entry of 10^4(2^.09) ENTER results in the same answer.\r
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\n" ); document.write( "\n" ); document.write( "now i'll use e.\r
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\n" ); document.write( "\n" ); document.write( "10,000 * e ^ .03t, when t is equal to 3, is calculated as follows in the TI-84 Plus calculator.\r
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\n" ); document.write( "\n" ); document.write( "you enter 10000*2ndLN.09) and the calculator tells you the answer is 10941.74284\r
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\n" ); document.write( "\n" ); document.write( "2ndLN gets you e^( which you then fill in with .09).\r
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\n" ); document.write( "\n" ); document.write( "try it out and see if you get the answer you are looking for.\r
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