document.write( "Question 1118964: 5 cards are chosen from an ordinary deck of cards to form a poker hand. What is the probability
\n" ); document.write( "that the hand has
\n" ); document.write( "at most
\n" ); document.write( "2 face cards? \n" ); document.write( "

Algebra.Com's Answer #734444 by greenestamps(13203) $\"\"$ $\"About$

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\n" ); document.write( "# of ways to get 0 face cards: choose 0 of the 12 face cards and 5 of the 40 other cards.
\n" ); document.write( " $\"C%2812%2C0%29%2AC%2840%2C5%29+=+658008\"$

\n" ); document.write( "# of ways to get 1 face card: choose 1 of the 12 face cards and 4 of the 40 other cards.
\n" ); document.write( " $\"C%2812%2C1%29%2AC%2840%2C4%29+=+1096680\"$

\n" ); document.write( "# of ways to get 2 face cards: choose 2 of the 12 face cards and 3 of the 40 other cards.
\n" ); document.write( " $\"C%2812%2C2%29%2AC%2840%2C3%29+=+652080\"$

\n" ); document.write( "The probability of getting at most 2 face cards is the total number of ways of getting at most 2 face cards, divided by the total number of ways of choosing 5 cards from the full deck of 52:

\n" ); document.write( " $\"%28658008%2B1096680%2B652080%29%2F2598960+=+0.926\"$ to 3 decimal places. \n" ); document.write( "

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