document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=100572>Question 100572</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how much pure gold should be melted with 15 grams of 14-karat gold to produce 18-karat gold? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #73444 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=73444\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> how much pure gold should be melted with 15 grams of 14-karat gold to produce 18-karat gold?<BR>\n" );
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document.write( "Pure gold is 24 karat<BR>\n" );
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document.write( "Let x = amt of pure gold<BR>\n" );
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document.write( "A karat equation:<BR>\n" );
document.write( "14(15) + 24(x) = 18(x + 15)<BR>\n" );
document.write( "210 + 24x = 18x + 270<BR>\n" );
document.write( "24x - 18x = 270 - 210<BR>\n" );
document.write( "6x = 60<BR>\n" );
document.write( "x = 10 grams of pure gold required<BR>\n" );
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document.write( "Check solution of x = 10:<BR>\n" );
document.write( "14(15) + 24(10) = 18(25) </SPAN>\n" );
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