document.write( "Question 100884: 6p+22=10 \n" ); document.write( "
Algebra.Com's Answer #73438 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
\"6p%2B22=10\" Start with the given equation\r
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\n" ); document.write( "\n" ); document.write( "\"6p%2Bcross%2822-22%29=10-22\" Subtract 22 from both sides\r
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\n" ); document.write( "\n" ); document.write( "\"6p=10-22\" \r
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\n" ); document.write( "\n" ); document.write( "\"6p=-12\" Subtract 22 from 10 to get -12\r
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\n" ); document.write( "\n" ); document.write( "\"cross%286%2F6%29p=-12%2F6\" Divide both sides by 6 to isolate p\r
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\n" ); document.write( "\n" ); document.write( "\"p=-12%2F6\" \r
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\n" ); document.write( "\n" ); document.write( "\"p=-2\" Reduce\r
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\n" ); document.write( "\n" ); document.write( "\"6p%2B22=10\" Start with the given equation\r
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\n" ); document.write( "\n" ); document.write( "\"6%28-2%29%2B22=10\" Plug in \"p=-2\"\r
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\n" ); document.write( "\n" ); document.write( "\"-12%2B22=10\" Multiply\r
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\n" ); document.write( "\n" ); document.write( "\"10=10\" Add. Since the equation is true, the solution \"p=-2\" works
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