document.write( "Question 1118952: Hi can you help me solve this problem please?
\n" ); document.write( "\"Coco has a jar containing pennies and nickels that add up to a total of $9.20. If she could switch the number of pennies with the number of nickels, there would be $26.80 worth of coins in the jar. How many pennies and nickels are in the jar?\"\r
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Algebra.Com's Answer #734365 by ikleyn(52814) $\"\"$ $\"About$

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document.write( "Let P the number of pennies and N be the number of nickels in the jar.\r\n" );
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document.write( "Then the coins worth is  P + 5N  cents  and the equation is\r\n" );
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document.write( "P + 5N =  920     (1)     (cents)\r\n" );
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document.write( "Now, under the \"if\" scenario, it would be P nickels and N pennies, that would worth 5P + N  cents.  So, the second equation is\r\n" );
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document.write( "5P + N = 2680     (2)    (cents)\r\n" );
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document.write( "Thus you have this system of two equation in 2 unknowns\r\n" );
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document.write( "P + 5N =  920     (1) \r\n" );
document.write( "5P + N = 2680     (2)\r\n" );
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document.write( "To solve it, from eq(1) express  P = 920-5N, and then substitute it into eq(2), replacing P. You will get a single equation for only one unknown N:\r\n" );
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document.write( "5*(920-5N) + N = 2680.\r\n" );
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document.write( "Simplify and solve for N:\r\n" );
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document.write( "4600 - 25N + N = 2680.\r\n" );
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document.write( "-24N = 2680 - 4600\r\n" );
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document.write( "-24N = -1920  ====>  N =  = 80.\r\n" );
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document.write( "Thus there are 80 nickels in the original collection.\r\n" );
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document.write( "Then the number of pennies is  P = 920 - 5N = 920 - 5*80 = 920 - 400 = 520.\r\n" );
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