document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=100882>Question 100882</A>: <I><SPAN STYLE=\"word-break: break-all;\"> decide all values of b in the following equations that will give one or more real number solutions.\r<BR>\n" );
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document.write( "(A) 3x^2+bx-3=0<BR>\n" );
document.write( "(B) 5x^2+bx+1=0<BR>\n" );
document.write( "(c) -3x^2+bx-3=0\r<BR>\n" );
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document.write( "(D) Write a rule for judging if an equation has solutions by looking at it in standard form </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #73436 by </B><A HREF=/tutors/aboutme.mpl?userid=edjones><B>edjones(8007)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=edjones><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=edjones><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=73436\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> D) Rule: If (b^2-4ac) >= 0 then you have a real number solution.<BR>\n" );
document.write( "A)-4ac=-4*3*-3=36 so b can be any real number.<BR>\n" );
document.write( "B)-4ac=-4*5*1=-20 so if b<= -sqrt(20)= -2sqrt(5) or b>= 2sqrt(5) there will be a real number solution.<BR>\n" );
document.write( "C)-4ac=-4*-3*-3=-36 so if b<=-6 or b>=6 there will be a real number solution.<BR>\n" );
document.write( "Ed<BR>\n" );
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