document.write( "Question 1118926: y=1/2x^2+x-4 \r
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document.write( " Sketch the following quadratic relationship by finding the x-intercepts , the y intercept, axis of symmetry, mirror of the y intercept and the vertex \n" );
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Algebra.Com's Answer #734345 by greenestamps(13200)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( " \n" ); document.write( "Factor out the leading coefficient and complete the square in x to find the vertex and axis of symmetry. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "The vertex is (-1,-9/2); the axis of symmetry is x=-1. \n" ); document.write( "The y-intercept is where x=0; setting x=0 in the original form of the equation we see the y-intercept is (0,-4). \n" ); document.write( "Then since the axis of symmetry is x = -1, the mirror of the y-intercept is (-2,-4). \n" ); document.write( "To find the x-intercepts (the zeros of the function), the easiest way is to look at the original equation after the leading coefficient has been factored out: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "The zeros are -4 and +2; the x-intercepts are (-4,0) and (2,0). \n" ); document.write( " |