document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1118896>Question 1118896</A>: <I><SPAN STYLE=\"word-break: break-all;\"> About 3% of the population has a particular genetic mutation. 300 people are randomly selected.\r<BR>\n" );
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document.write( "Find the standard deviation for the number of people with the genetic mutation in such groups of 300. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #734330 by </B><A HREF=/tutors/aboutme.mpl?userid=addingup><B>addingup(3677)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=addingup><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=addingup><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=734330\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let X be a random variable denoting the number of people having genetic mutation out of 300 people. X follows Binomial Distribution with parameters n = 300 and <BR>\n" );
document.write( "p = 0.03<BR>\n" );
document.write( "The standard deviation of X is:<BR>\n" );
document.write( "sqrt(n*p*(1-p)) = sqrt(300*0.03*(1-0.03)) = 8.73 = sqrt 8.73 = 2.955<BR>\n" );
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