document.write( "Question 1118829: A ship sails in the direction S 70 degrees W for 3 hours at 50km/h . It then changes direction to travel a bearing of 120 degrees for 4 hours at the same speed. Show with a diagram.\r
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document.write( "a) After 7 hours, how far is the ship from its original position? Express your answer to the nearest whole kilometer.\r
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document.write( "b)To the nearest degree, what is the bearing of the final position of the ship from the original position?\r
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document.write( "Thank you
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Algebra.Com's Answer #734276 by solver91311(24713)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( " ![]() \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The turn from 70 west of south to bearing 120 is 130 degrees, hence Angle OAB is 50 degrees. 3 hours at 50 km/hr is 150 km, and 4 hours at 50 km/hr is 200 km. With two sides and the included angle, use the Law of Cosines to calculate the measure of Segment OB, the current ship's displacement from the origin.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Then use the Law of Sines to calculate Angle AOB. Subtract 70 degrees from Angle AOB, then subtract that difference from 180 degrees to obtain the final bearing. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "John \n" ); document.write( " \n" ); document.write( "My calculator said it, I believe it, that settles it \n" ); document.write( " ![]() \n" ); document.write( " |