document.write( "Question 1118836: The strength of a rectangular beam varies jointly as its width and the square of its depth. If the strength of a beam 2 inches wide by 10 inches deep is 1000 pounds per square inch, what is the strength of a beam 4 inches wide and 8 inches deep \n" ); document.write( "
Algebra.Com's Answer #734267 by greenestamps(13215)\"\" \"About 
You can put this solution on YOUR website!


\n" ); document.write( "The other tutor derived the specific formula for calculating the strength of a beam, using the given information to calculate the constant of variation. So they didn't answer your question; but they made it easy for you to plug in numbers to get the answer.

\n" ); document.write( "In relatively simple problems like this, I find it more difficult and time-consuming to find the constant of variation the way the other tutor did.

\n" ); document.write( "Instead, I find it easier to apply factors to the given information to find how the strength is changed with the new information.

\n" ); document.write( "The load limit is 1000 pounds per square inch when the beam is 2 inches wide and 10 inches deep. In the new beam, the width is 4 inches (times 2) and the depth is 8 inches (times 4/5).

\n" ); document.write( "Then since the variation is jointly with the width and the square of the depth, the new load limit is

\n" ); document.write( "\"%281000%29%2A%282%29%2A%28%284%2F5%29%5E2%29+=+1280\"

\n" ); document.write( "The load limit of the new beam is 1280 pounds per square inch.
\n" ); document.write( "
\n" );