document.write( "Question 1118790: Town X and Town Y are 560 KM apart. At 11 A.M., a van leaves Town X for Town Y, Travelling at a constant rate of speed. At the same time, a bus leaves for Town Y from Town X, also travelling at a constant rate of speed. The 2 vehicle pass each other at 1.20 P.M. The average speed of the van is 60 km per hr faster than the bus.\r
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document.write( "a) Find the van's average rate of speed?\r
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document.write( "b) How far is the bus from Town X when it passes the van? \n" );
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Algebra.Com's Answer #734220 by josgarithmetic(39625)![]() ![]() ![]() You can put this solution on YOUR website! 11AM to 1:20PM is 2 hours 20 minutes.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "r, bus speed \n" ); document.write( "r+60, van speed\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Distance used between the two was 560 kilometers.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Solve.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "-\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "- \n" ); document.write( " \n" ); document.write( "- \n" ); document.write( " \n" ); document.write( " |