document.write( "Question 1118750: Find the area of a regular hexagon with the given measurement.
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Algebra.Com's Answer #734183 by ikleyn(52832)\"\" \"About 
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document.write( "The area of a regular hexagon is six times the area of central equilateral triangle.\r\n" );
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document.write( "You are given the apothem = \"2%2Asqrt%283%29\" of the regular hexagon, which is the altitude of the equilateral triangle.\r\n" );
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document.write( "Let x be the side length of the hexagon.\r\n" );
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document.write( "It is also the side length of the equilateral triangle.\r\n" );
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document.write( "In an equilateral triangle with the side length x the altitude is  \"x%2A%28sqrt%283%29%2F2%29%29\".   //  Every student who study/studied Geometry must know it.\r\n" );
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document.write( "Therefore,  \"x%2A%28sqrt%283%29%2F2%29\" = \"2%2Asqrt%283%29\",  which implies  x= 4.\r\n" );
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document.write( "Thus the side length of the regular hexagon is 4 units, same as the side length of the equilateral triangle.\r\n" );
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document.write( "Hence, the area of the equilateral triangle is  \"%281%2F2%29%2A4%2A%284%2Asqrt%283%29%2F2%29\" = \"4%2Asqrt%283%29\" square units.\r\n" );
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document.write( "Then the area of the given hexagon is 6 times this value, i.e. \"24%2Asqrt%283%29\" square units.\r\n" );
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