document.write( "Question 1118746: Ms. Brown invested $24,000 in two accounts, one yielding 5% interest and the other yielding 12%. If she received a total of $1,900 in interest at the end of the year, how much did she invest in each account? \n" ); document.write( "
Algebra.Com's Answer #734167 by addingup(3677)![]() ![]() You can put this solution on YOUR website! At 5%: x \n" ); document.write( "At 12%: 24000-x \n" ); document.write( "0.05x + 0.12(24000-x) = 1900 \n" ); document.write( "0.05x + 2880-0.12x = 1900 \n" ); document.write( "-0.07x = -980 \n" ); document.write( "x = 14,000 \n" ); document.write( "Ms. Brown invested 14,000 at 5% and 24,000-14,000 = 10,000 at 12% \n" ); document.write( "~~~~~~~~~~~~~~~~~ \n" ); document.write( "Check: \n" ); document.write( "14,000(0.05) + 10,000(0.12) = 1,900 \n" ); document.write( "700 + 1,200 = 1,900 Correct \n" ); document.write( " \n" ); document.write( " |